Identify the element for which electronic configuration in +3 oxidation state is [Ar]3d5 :
Solution
Mn(25) = [Ar]3d<sup>5</sup>4s<sup>2</sup>
<br><br>Mn<sup>+3</sup> = [Ar]3d<sup>4</sup>4s<sup>0</sup>
<br><br>Ru-belongs to 4d transition series
<br><br>Co (27) = [Ar]3d<sup>7</sup>4s<sup>2</sup>
<br><br>Co<sup>+3</sup> = [Ar]3d<sup>6</sup>4s<sup>0</sup>
<br><br>Fe(26) = [Ar]3d<sup>6</sup>4s<sup>2</sup>
<br><br>Fe<sup>+3</sup> = [Ar]3d<sup>5</sup>4s<sup>0</sup>
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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