During the qualitative analysis of $\mathrm{SO}_{3}^{2-}$ using dilute $\mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{SO}_{2}$ gas is evolved which turns $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ solution (acidified with dilute $\mathrm{H}_{2} \mathrm{SO}_{4}$) :
Solution
<p>$$\mathrm{S{O_2} + C{r_2}O_7^{2 - }\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{}} \mathop {C{r^{3 + }}}\limits_{(green)} + SO_4^{2 - }}$$</p>
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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