What is the spin-only magnetic moment value (BM) of a divalent metal ion with atomic number 25, in it's aqueous solution?
Solution
<sub>25</sub>Mn = [Ar]3d<sup>5</sup> 4s<sup>2</sup><br>
Mn<sup>2+</sup> = [Ar]3d<sup>5</sup> 4s<sup>0</sup><br><br>
No. of unpaired electron (n) = 5<br><br>
$\mu = \sqrt {n\left( {n + 2} \right)} \,BM$<br><br>
$= \sqrt {5 \times 7} {\rm{ }} = \sqrt {35} {\rm{ }} = {\rm{ }}5.92{\rm{ }}$ BM
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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