In neutral or alkaline solution, $\mathrm{MnO}_{4}^{-}$ oxidises thiosulphate to :
Solution
$8 \mathrm{MnO}_{4}^{-}+3 \mathrm{~S}_{2} \mathrm{O}_{3}^{2-}+ \mathrm{H}_{2} \mathrm{O}\rightarrow 8 \mathrm{MnO}_{2}+6 \mathrm{SO}_{4}^{2-}+$ $2 \mathrm{OH}^{-}$
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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