Given below are two statements :
Statement I : CeO2 can be used for oxidation of aldehydes and ketones.
Statement II : Aqueous solution of EuSO4 is a strong reducing agent.
In the light of the above statements, choose the correct answer from the options given below :
Solution
The +3 oxidation state of lanthanide is most
stable and therefore lanthanide in +4 oxidation
state has strong tendence to gain e<sup>–</sup>
and
converted into +3 and therefore act as strong
oxidizing agent.
eg Ce<sup>+4</sup>
<br>And therefore CeO<sub>2</sub>
is used to oxidized alcohol
aldehyde and ketones.
<br><br>Lanthanide in +2 oxidation state has strong
tendency to loss e<sup>–</sup>
and converted into +3
oxidation state therefore act as strong reducing
agent.
<br><br>$\therefore$ EuSO<sub>4</sub> act as a strong reducing agent.
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
This question is part of PrepWiser's free JEE Main question bank. 155 more solved questions on d and f Block Elements are available — start with the harder ones if your accuracy is >70%.