In K₂Cr₂O₇, the oxidation state of Cr is $x$.
Answer (integer)
6
Solution
K₂Cr₂O₇: 2(+1) + 2x + 7(-2) = 0 ⇒ 2 + 2x - 14 = 0 ⇒ 2x = 12 ⇒ x = +6.
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Important Compounds of Transition Metals
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