The first transition series metal ' $M$ ' has the highest enthalpy of atomisation in its series. One of its aquated ion $\left(\mathrm{M}^{\mathrm{n}+}\right)$ exists in green colour. The nature of the oxide formed by the above $\mathrm{M}^{\mathrm{n}+}$ ion is:
Solution
<p>In the 3d transition series, Vanadium (V) has the highest enthalpy of atomization. The ion $\mathrm{V}^{3+}$ is known to exhibit a green color in its aqueous form. The oxide formed by the $\mathrm{V}^{3+}$ ion is $\mathrm{V}_2 \mathrm{O}_3$, which is classified as a basic oxide.</p>
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
This question is part of PrepWiser's free JEE Main question bank. 155 more solved questions on d and f Block Elements are available — start with the harder ones if your accuracy is >70%.