The spin only magnetic moments (in BM) for free Ti3+, V2+ and Sc3+ ions respectively are :
(At.No. Sc : 21, Ti : 22, V : 23)
Solution
$\mu = \sqrt {n(n + 2)} BM$<br><br>$$\matrix{
{T{i^{ + 3}} = [Ar]3{d^1}} & {n = 1} & {\mu = 1.73\,BM} \cr
{{V^{ + 2}} = [Ar]3{d^3}} & {n = 3} & {\mu = 3.87\,BM} \cr
{S{c^{ + 3}} = [Ar]3{d^0}4{s^0}} & {n = 0} & {\mu = 0} \cr
} $$
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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