$\mathrm{KMnO}_4$ decomposes on heating at $513 \mathrm{~K}$ to form $\mathrm{O}_2$ along with
Solution
<p>$$\mathrm{KMnO}_4 \xrightarrow{\Delta} \mathrm{K}_2 \mathrm{MnO}_4+\mathrm{MnO}_2+\mathrm{O}_2$$</p>
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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