A chloride salt solution acidified with dil.HNO$_3$ gives a curdy white precipitate, [A], on addition of AgNO$_3$. [A] on treatment with NH$_4$OH gives a clear solution B. A and B are respectively :
Solution
$\mathrm{Cl}^{-}(\mathrm{aq})+\mathrm{AgNO}_{3}(\mathrm{aq}) \stackrel{\text { dil } \mathrm{HNO}_{3}}{\longrightarrow} \underset{(\mathrm{A})}{\mathrm{AgCl}} \downarrow$
<br/><br/>
$$
\mathrm{AgCl} \downarrow+2 \mathrm{NH}_4 \mathrm{OH}(\mathrm{aq}) \rightarrow\underset{(B)}{\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right]} \mathrm{Cl}(\mathrm{aq})+2 \mathrm{H}_2 \mathrm{O}
$$
<br/><br/>
$\therefore(\mathrm{A})$ is $\mathrm{AgCl}$ and $(\mathrm{B})$ is $\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right] \mathrm{Cl}$
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
This question is part of PrepWiser's free JEE Main question bank. 155 more solved questions on d and f Block Elements are available — start with the harder ones if your accuracy is >70%.