Medium MCQ +4 / -1 PYQ · JEE Mains 2022

The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?

  1. A Ce (At. No. 58) Correct answer
  2. B La (At. No. 57)
  3. C Lu (At. No. 71)
  4. D Gd (At. No. 64)

Solution

Ce → [Xe]4f<sup>1</sup> 5d<sup>1</sup> 6s<sup>2</sup><br/><br/> Ce<sup>+4</sup> → [xe] 4f° 5d° 6s°<br/><br/> Cerium in +4 oxidation state acquires inert gas configuration.

About this question

Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals

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