5 g of zinc is treated separately with an excess
of
(a) dilute hydrochloric acid and
(b) aqueous sodium hydroxide.
The ratio of the volumes of H2 evolved in these
two reactions is :
Solution
Zn + 2dil. HCl $\to$ ZnCl<sub>2</sub> + H<sub>2</sub>
<br><br>Zn + 2NaOH $\to$ Na<sub>2</sub>ZnO<sub>2</sub> + H<sub>2</sub>
<br><br>From one mole of Zn, 1 mol of H<sub>2</sub> is produced
by both NaOH and HCl.
<br><br>The ratio of the volume of H<sub>2</sub> is 1 : 1
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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