Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is ____________.
Answer (integer)
3
Solution
Manganese $(\mathrm{VI})$ disproportionates in acidic medium as
<br/><br/>
$3 \mathrm{MnO}_{4}^{2-}+4 \mathrm{H}^{+} \longrightarrow 2 \mathrm{MnO}_{4}^{-}+\mathrm{MnO}_{2}+2 \mathrm{H}_{2} \mathrm{O}$
<br/><br/>
The difference in oxidation states of $\mathrm{Mn}$ in the products formed $=7-4=3$
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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