The spin-only magnetic moment value of the compound with strongest oxidizing ability among $\mathrm{MnF}_{4}, \mathrm{MnF}_{3}$ and $\mathrm{MnF}_{2}$ is ____________ B.M. [nearest integer]
Answer (integer)
5
Solution
$\mathrm{MnF}_{3}$ has the strongest oxidizing ability
<br/><br/>
$$
\left[\begin{array}{l}
\mathrm{E}_{\mathrm{Mn}^{+3} / \mathrm{Mn}^{+2}}^{\circ} \simeq 1.57 \mathrm{~V} \\
\& \,\,\mathrm{E}_{\mathrm{Mn}^{+4} / \mathrm{Mn}^{+2}}^{\circ} \simeq 1.2 \mathrm{~V}
\end{array}\right]
$$
<br/><br/>
So, spin only magnetic moment
<br/><br/>
$=\sqrt{4(4+2)}=\sqrt{24} \text { B.M. }$
<br/><br/>
$\simeq 5$
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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