Number of electrons present in 4f orbital of Ho3+ ion is ____________. (Given Atomic No. of Ho = 67)
Answer (integer)
10
Solution
Ho = [Xe]4f<sup>11</sup>6s<sup>2</sup><br><br>Ho<sup>3+</sup> = [Xe] 4f<sup>10</sup><br><br>So number of e<sup>$-$</sup> present in 4f is 10.
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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