A chemist has 4 samples of artificial sweetener
A, B, C and D. To identify these samples, he
performed certain experiments and noted the
following observations :
(i) A and D both form blue-violet colour with
ninhydrin.
(ii) Lassaigne extract of C gives positive
AgNO3 test and negative Fe4[Fe(CN)6]3 test.
(iii) Lassaigne extract of B and D gives positive
sodium nitroprusside test
Based on these observations which option is
correct ?
Solution
(i) A and D give positive test with ninhydrin because both have free carboxylic and amine group. Both aspartame and alitame contains
amino acids.
<br><br>(ii) Lassaigne extract give +ve test with
AgNO<sub>3</sub>. So Cl is present, –ve test with
Fe<sub>4</sub>[Fe(CN)<sub>6</sub>]<sub>3</sub> means N is absent. So it
can't be Aspartame or Saccharine or
Alitame, so C is sucralose.
<br><br>(iii) Lassaigne solution of B and D given +ve
sodium nitroprusside test, so it is a sulphur containing compound,
Saccharine and Alitame also contains sulphur.
<br><br>$\therefore$ A = Aspartame, B = Saccharin
<br><br>C = Sucralose, D = Alitame.
About this question
Subject: Chemistry · Chapter: Chemistry in Everyday Life · Topic: Drugs and Medicines
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