The half life for the decomposition of gaseous compound $\mathrm{A}$ is $240 \mathrm{~s}$ when the gaseous pressure was 500 Torr initially. When the pressure was 250 Torr, the half life was found to be $4.0$ min. The order of the reaction is ______________. (Nearest integer)
Answer (integer)
1
Solution
$\left(\mathrm{t}_{1 / 2}\right)_{\mathrm{A}}=240 \mathrm{~s}$ when $\mathrm{P}=500$ torr
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$\left(t_{1 / 2}\right)_{A}=4 \min =4 \times 60=240$ sec when $P=250$ torr
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If means half-life is independent of concentration of reactant present.
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$\therefore$ Order of reaction $=1$
About this question
Subject: Chemistry · Chapter: Chemical Kinetics · Topic: Rate of Reaction
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