For a reaction $A \xrightarrow{\mathrm{K}_1} \mathrm{~B} \xrightarrow{\mathrm{K}_2} \mathrm{C}$ If the rate of formation of B is set to be zero then the concentration of B is given by :
Solution
<p>To determine the concentration of $ \mathrm{B} $ when the rate of formation of $ \mathrm{B} $ is set to zero, let's consider the reaction sequence:</p>
<p>$$ \mathrm{A} \xrightarrow{\mathrm{K}_1} \mathrm{B} \xrightarrow{\mathrm{K}_2} \mathrm{C} $$</p>
<p>The rate of formation of $ \mathrm{B} $ from $ \mathrm{A} $ is given by:</p>
<p>$\text{Rate of formation of } \mathrm{B} = \mathrm{K}_1[\mathrm{A}]$</p>
<p>The rate of consumption of $ \mathrm{B} $ to form $ \mathrm{C} $ is given by:</p>
<p>$\text{Rate of consumption of } \mathrm{B} = \mathrm{K}_2[\mathrm{B}]$</p>
<p>At steady state, where the rate of formation of $ \mathrm{B} $ is set to zero, the rate of formation of $ \mathrm{B} $ is equal to the rate of its consumption. Therefore, we have:</p>
<p>$\mathrm{K}_1[\mathrm{A}] = \mathrm{K}_2[\mathrm{B}]$</p>
<p>Solving for $ [\mathrm{B}] $, we get:</p>
<p>$[\mathrm{B}] = \frac{\mathrm{K}_1}{\mathrm{K}_2} [\mathrm{A}]$</p>
<p>Therefore, the correct concentration of $ \mathrm{B} $ is:</p>
<p><strong>Option D:</strong> $\left(\frac{\mathrm{K}_1}{\mathrm{K}_2}\right)[\mathrm{A}]$</p>
About this question
Subject: Chemistry · Chapter: Chemical Kinetics · Topic: Rate of Reaction
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