The equation
k = (6.5 $\times$ 1012s$-$1)e$-$26000K/T
is followed for the decomposition of compound A. The activation energy for the reaction is ________ kJ mol$-$1. [nearest integer]
(Given : R = 8.314 J K$-$1 mol$-$1)
Answer (integer)
216
Solution
$k=A e^{\frac{-E_{a}}{R T}}$
<br/><br/>
$$
\begin{aligned}
\frac{E_{a}}{R T} &=\frac{26000}{T} \\\\
E_{a} &=26000 \times 8.314 \\\\
&=216164 \mathrm{~J} \\\\
&=216 \mathrm{~kJ}
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: Chemical Kinetics · Topic: Rate of Reaction
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