Match List-I with List-II :
| List-I (Species) |
List-II (Hybrid Orbitals) |
||
|---|---|---|---|
| (a) | $S{F_4}$ | (i) | $s{p^3}{d^2}$ |
| (b) | $I{F_5}$ | (ii) | ${d^2}s{p^3}$ |
| (c) | $NO_2^ +$ | (iii) | $s{p^3}d$ |
| (d) | $NH_4^ +$ | (iv) | $s{p^3}$ |
| (v) | $sp$ |
Choose the correct answer from the options given below :
Solution
(a) SF<sub>4</sub> - sp<sup>3</sup>d hybridization<br><br>(b) IF<sub>5</sub> - sp<sup>3</sup>d<sup>2</sup> hybridization<br><br>(c) NO$_2^ +$ - sp hybridization<br><br>(d) NH$_4^ +$ - sp<sup>3</sup> hybridization
About this question
Subject: Chemistry · Chapter: Chemical Bonding and Molecular Structure · Topic: Ionic and Covalent Bonding
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