Match List - I with List - II.
| List - I | List - II | ||
|---|---|---|---|
| (A) | $\psi_{\mathrm{MO}}=\psi_{\mathrm{A}}-\psi_{\mathrm{B}}$ | (I) | Dipole moment |
| (B) | $\mu=Q \times r$ | (II) | Bonding molecular orbital |
| (C) | $\frac{\mathrm{N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}}{2}$ | (III) | Anti-bonding molecular orbital |
| (D) | $\psi_{\mathrm{MO}}=\psi_{\mathrm{A}}+\psi_{\mathrm{B}}$ | (IV) | Bond order |
Choose the correct answer from the options given below :
Solution
$\Psi_{A}-\Psi_{B}=\Psi_{M O}$ is anti-boding molecular orbital
<br/><br/>
$$
\begin{aligned}
&\mu=Q \times r \text { is dipole moment } \\\\
&\frac{N_{b}-N_{a}}{2}=\text { bond order } \\\\
&\Psi_{\mathrm{A}}+\Psi_{\mathrm{B}}=\Psi_{\mathrm{MO}} \text { is boding molecular orbital. }
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: Chemical Bonding and Molecular Structure · Topic: Ionic and Covalent Bonding
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