Easy MCQ +4 / -1 PYQ · JEE Mains 2025

Which of the following molecule(s) show/s paramagnetic behavior?

A. $\mathrm{O}_2$

B. $\mathrm{N}_2$

C. $\mathrm{F}_2$

D. $\mathrm{S}_2$

E. $\mathrm{Cl}_2$

Choose the correct answer from the options given below:

  1. A A & C only
  2. B A & E Only
  3. C A & D Only Correct answer
  4. D B Only

Solution

<p>No. of unpaired $\mathrm{e}^{-}$</p> <p><style type="text/css"> .tg {border-collapse:collapse;border-spacing:0;} .tg td{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; overflow:hidden;padding:10px 5px;word-break:normal;} .tg th{border-color:black;border-style:solid;border-width:1px;font-family:Arial, sans-serif;font-size:14px; font-weight:normal;overflow:hidden;padding:10px 5px;word-break:normal;} .tg .tg-baqh{text-align:center;vertical-align:top} </style> <table class="tg" style="undefined;table-layout: fixed; width: 245px"><colgroup> <col style="width: 75px"> <col style="width: 80px"> <col style="width: 90px"> </colgroup> <thead> <tr> <th class="tg-baqh">(A)</th> <th class="tg-baqh">$\mathrm{O}_2$<br></th> <th class="tg-baqh">2</th> </tr></thead> <tbody> <tr> <td class="tg-baqh">(B)</td> <td class="tg-baqh">$\mathrm{N}_2$</td> <td class="tg-baqh">0</td> </tr> <tr> <td class="tg-baqh">(C)</td> <td class="tg-baqh">$\mathrm{F}_2$</td> <td class="tg-baqh">0</td> </tr> <tr> <td class="tg-baqh">(D)</td> <td class="tg-baqh">$\mathrm{S}_2$</td> <td class="tg-baqh">2</td> </tr> <tr> <td class="tg-baqh">(E)</td> <td class="tg-baqh">$\mathrm{Cl}_2$</td> <td class="tg-baqh">0</td> </tr> </tbody> </table></p> <p>If species contain unpaired electron than it is paramagnetic.</p> <p>So A & D are paramagnetic.</p>

About this question

Subject: Chemistry · Chapter: Chemical Bonding and Molecular Structure · Topic: Ionic and Covalent Bonding

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