Match List - I with List - II:
| List - I Species | List - II Geometry/Shape | ||
|---|---|---|---|
| A. | $\mathrm{H_3O^+}$ | I. | Tetrahedral |
| B. | Acetylide anion | II. | Linear |
| C. | $\mathrm{NH_4^+}$ | III. | Pyramidal |
| D. | $\mathrm{ClO_2^-}$ | IV. | Bent |
Choose the correct answer from the options given below:
Solution
<p>Let's consider each species in List I and determine their geometries/shapes.</p>
<p>A. $\mathrm{H_3O^+}$: This ion is formed by the addition of a proton to a water molecule. The central atom (O) is surrounded by three Hydrogen atoms and one lone pair, making its shape pyramidal.</p>
<p>B. Acetylide anion: The acetylide ion ($\mathrm{C_2H^-}$ or $\mathrm{C_2^{2-}}$) has a linear geometry as the three atoms are in a straight line.</p>
<p>C. $\mathrm{NH_4^+}$: The ammonium ion has a central nitrogen atom surrounded by four hydrogen atoms, giving it a tetrahedral geometry.</p>
<p>D. $\mathrm{ClO_2^-}$: The chlorite ion has a central chlorine atom surrounded by two oxygen atoms and one lone pair, which gives it a bent or V-shaped geometry.</p>
<p>Matching these to List II, we get:</p>
<p>A. $\mathrm{H_3O^+}$ - III. Pyramidal<br/><br/>
B. Acetylide anion - II. Linear<br/><br/>
C. $\mathrm{NH_4^+}$ - I. Tetrahedral<br/><br/>
D. $\mathrm{ClO_2^-}$ - IV. Bent</p>
About this question
Subject: Chemistry · Chapter: Chemical Bonding and Molecular Structure · Topic: Ionic and Covalent Bonding
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