Match List I with List II

	LIST I (Molecule)		LIST II (Shape)
A.	$\mathrm{NH_3}$	I.	Square pyramid
B.	$\mathrm{BrF_5}$	II.	Tetrahedral
C.	$\mathrm{PCl_5}$	III.	Trigonal pyramidal
D.	$\mathrm{CH_4}$	IV.	Trigonal bipyramidal

Choose the correct answer from the options given below:

<p>To match the molecules in List I with their corresponding shapes in List II, we need to consider the electronic geometry and the VSEPR (Valence Shell Electron Pair Repulsion) theory. Here’s the detailed analysis:</p> <p><b>$\mathrm{NH_3}$ (Ammonia)</b>: Ammonia has a central nitrogen atom bonded to three hydrogen atoms and has one lone pair of electrons. This leads to a trigonal pyramidal shape.</p> <p><b>$\mathrm{BrF_5}$ (Bromine pentafluoride)</b>: Bromine pentafluoride has a central bromine atom bonded to five fluorine atoms and has one lone pair of electrons. This leads to a square pyramidal shape.</p> <p><b>$\mathrm{PCl_5}$ (Phosphorus pentachloride)</b>: Phosphorus pentachloride has a central phosphorus atom bonded to five chlorine atoms and no lone pairs. This results in a trigonal bipyramidal shape.</p> <p><b>$\mathrm{CH_4}$ (Methane)</b>: Methane has a central carbon atom bonded to four hydrogen atoms with no lone pairs, forming a tetrahedral structure.</p> <p>Using the above analyses, we can match the molecules and shapes as follows:</p> <ul> <li>A ($\mathrm{NH_3}$) - III (Trigonal pyramidal)</li> <li>B ($\mathrm{BrF_5}$) - I (Square pyramid)</li> <li>C ($\mathrm{PCl_5}$) - IV (Trigonal bipyramidal)</li> <li>D ($\mathrm{CH_4}$) - II (Tetrahedral)</li> </ul> <p>Therefore, the correct matching is option B:</p> <p><b>Option B: A-III, B-I, C-IV, D-II</b></p>