Match List I with List II
| List - I | List - II | ||
|---|---|---|---|
| (A) | Glucose/$\mathrm{NaHCO_3/\Delta}$ | (I) | Gluconic acid |
| (B) | $\text { Glucose } / \mathrm{HNO}_3$ | (II) | No reaction |
| (C) | $\text { Glucose } / \mathrm{HI} / \Delta$ | (III) | n-hexane |
| (D) | Glucose/Bromine water | (IV) | Saccharic acid |
Choose the correct answer from the options given below:
Solution
<p>Glucose $\xrightarrow[\Delta]{\mathrm{NaHCO}_3}$ no reaction</p>
<p>Glucose $\xrightarrow[\Delta]{\mathrm{HNO}_3}$ saccharic acid</p>
<p>Glucose $\xrightarrow[\Delta]{\mathrm{HI}}$ n-hexane</p>
<p>Glucose $\xrightarrow[\Delta]{\mathrm{Br}_2}$ Gluconic acid</p>
About this question
Subject: Chemistry · Chapter: Biomolecules · Topic: Carbohydrates
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