The total number of hydrogen bonds of a DNA-double Helix strand whose one strand has the following sequence of bases is ________.
$$5^{\prime}-\mathrm{G}-\mathrm{G}-\mathrm{C}-\mathrm{A}-\mathrm{A}-\mathrm{A}-\mathrm{T}-\mathrm{C}-\mathrm{G}-\mathrm{G}-\mathrm{C}-\mathrm{T}-\mathrm{A}-3^{\prime}$$
Answer (integer)
33
Solution
<p>Two nucleic acid chains are wound about each other and held together by H bonds between pair of bases.</p>
<p>Adenine from two hydrogen bonds with thymine and Guanine form three hydrogen bond with cytosine.</p>
<p>$$5^{\prime} \mathrm{G}-\mathrm{G}-\mathrm{C}-\mathrm{A}-\mathrm{A}-\mathrm{A}-\mathrm{T}-\mathrm{C}-\mathrm{G}-\mathrm{G}-\mathrm{C}-\mathrm{T}-\mathrm{A}-3^{\prime}$$</p>
<p>In given DNA strand total seven guanine and cytosine bases which form total 21 H -bonds and six adenine and thymine base which will form total 12 H -bonds with other DNA strand.</p>
<p>Total no. of H bonds $=7 \times 3+6 \times 2=33$</p>
<p>Ans. 33</p>
About this question
Subject: Chemistry · Chapter: Biomolecules · Topic: Carbohydrates
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