For hydrogen atom, the orbital/s with lowest energy is/are :
(A) $\mathrm{4 s}$
(B) $3 \mathrm{p}_x$
(C) $3 \mathrm{~d}_{x^2-y^2}$
(D) $3 \mathrm{~d}_{z^2}$
(E) $4 \mathrm{p}_z$
Choose the correct answer from the options given below :
Solution
<p>In hydrogen atom the orbitals in a shell are degenerate means energy depends only on ' $n$ '</p>
<p>$$\therefore \mathrm{E}_{3 \mathrm{p}_{\mathrm{x}}}=\mathrm{E}_{3 \mathrm{~d}_{x^2-y^2}}=\mathrm{E}_{3 \mathrm{~d}_{z^2}}$$</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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