Hydrogen has three isotopes (A), (B) and (C). If the number of neutron(s) in (A), (B) and (C) respectively, are (x), (y) and (z), the sum of (x), (y) an (z) is :
Solution
Hydrogen has three isotopes
<br><br>(A) Protium (${}_1^1H$) has 0 neutron.
<br><br>(B) Deutrium (${}_1^2H$) has 1 neutrons.
<br><br>(C) Tritium (${}_1^3H$) has 2 neutrons.
<br><br>Total number of neutrons in three <br>isotopes of
hydrogen = 0 + 1 + 2 = 3
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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