The energy of one mole of photons of radiation of frequency $2 \times 10^{12} \mathrm{~Hz}$ in $\mathrm{J} ~\mathrm{mol}^{-1}$ is ___________. (Nearest integer)
[Given : $\mathrm{h}=6.626 \times 10^{-34} ~\mathrm{Js}$
$\mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23} \mathrm{~mol}^{-1}$]
Answer (integer)
798
Solution
<p>$\mathrm{E=nhv}$</p>
<p>$=(6.022\times10^{23})(6.626\times10^{-34})\times(2\times10^{12})$</p>
<p>$=798.03$ J</p>
<p>$\approx$ $798$ J</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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