The wave function $(\Psi)$ of $2 \mathrm{~s}$ is given by
$$
\Psi_{2 \mathrm{~s}}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{r}{a_0}\right) e^{-r / 2 a_0}
$$
At $r=r_0$, radial node is formed. Thus, $r_0$ in terms of $a_0$
Solution
<p>For radial node ${\psi _{2s}} = 0$</p>
<p>$\therefore$ $r = 2{a_0}$</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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