Easy MCQ +4 / -1 PYQ · JEE Mains 2023

The wave function $(\Psi)$ of $2 \mathrm{~s}$ is given by

$$ \Psi_{2 \mathrm{~s}}=\frac{1}{2 \sqrt{2 \pi}}\left(\frac{1}{a_0}\right)^{1 / 2}\left(2-\frac{r}{a_0}\right) e^{-r / 2 a_0} $$

At $r=r_0$, radial node is formed. Thus, $r_0$ in terms of $a_0$

  1. A $r_0=a_0$
  2. B $r_0=4 a_0$
  3. C $r_0=2 a_0$ Correct answer
  4. D $r_0=\frac{a_0}{2}$

Solution

<p>For radial node ${\psi _{2s}} = 0$</p> <p>$\therefore$ $r = 2{a_0}$</p>

About this question

Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model

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