For the Balmer series in the spectrum of H atom,
$\overline \nu = {R_H}\left\{ {{1 \over {n_1^2}} - {1 \over {n_2^2}}} \right\}$, the correct statements among (I) to (IV)
are :
(I) As wavelength decreases, the lines in the series converge
(II) The integer n1 is equal to 2
(III) The lines of longest wavelength corresponds to n2 = 3
(IV) The ionization energy of hydrogen can be calculated from wave number of these lines
Solution
For balmer series : n<sub>1</sub> = 2, n<sub>2</sub> = 3, 4, 5, .....$\infty$
<br><br>For longest wavelength n<sub>2</sub> = 3
<br><br>${1 \over \lambda } = R\left( {{1 \over {{2^2}}} - {1 \over {{3^2}}}} \right)$
<br><br>As wavelength decreases the lines in the
Balmer series converge. The correct
statements are (I), (II) and (III).
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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