Easy MCQ +4 / -1 PYQ · JEE Mains 2023

The number of s-electrons present in an ion with 55 protons in its unipositive state is

  1. A 10 Correct answer
  2. B 9
  3. C 12
  4. D 8

Solution

The number of protons in an element determines its atomic number, which is the number of electrons in a neutral atom of the element. The unipositive state of an ion indicates that it has lost one electron. Therefore, the number of electrons in a unipositive ion is one less than the atomic number.<br/><br/> The element with 55 protons is cesium (Cs), which is in group 1 of the periodic table. Group 1 elements have one valence electron in the s sublevel of their outermost energy level. <br/><br/> In a neutral atom of cesium, there are 55 electrons, with the electron configuration [Xe] 6s<sup>1</sup>. When cesium loses one electron to form a unipositive ion (Cs<sup>+</sup>), the resulting ion has 54 electrons.<br/><br/> Out of this 54 electrons s subshell has 10 electrons in 1s<sup>2</sup>, 2s<sup>2</sup>, 3s<sup>2</sup>, 4s<sup>2</sup>, 5s<sup>2</sup>.

About this question

Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model

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