The number of s-electrons present in an ion with 55 protons in its unipositive state is
Solution
The number of protons in an element determines its atomic number, which is the number of electrons in a neutral atom of the element. The unipositive state of an ion indicates that it has lost one electron. Therefore, the number of electrons in a unipositive ion is one less than the atomic number.<br/><br/>
The element with 55 protons is cesium (Cs), which is in group 1 of the periodic table. Group 1 elements have one valence electron in the s sublevel of their outermost energy level.
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In a neutral atom of cesium, there are 55 electrons, with the electron configuration [Xe] 6s<sup>1</sup>. When cesium loses one electron to form a unipositive ion (Cs<sup>+</sup>), the resulting ion has 54 electrons.<br/><br/>
Out of this 54 electrons s subshell has 10 electrons in 1s<sup>2</sup>, 2s<sup>2</sup>, 3s<sup>2</sup>, 4s<sup>2</sup>, 5s<sup>2</sup>.
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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