If the radius of the 3rd Bohr's orbit of hydrogen atom is r3 and the radius of 4th Bohr's orbit is r4. Then :
Solution
<p>We know,</p>
<p>$r = {r_0} \times {{{n^2}} \over z}$</p>
<p>For hydrogen atom,</p>
<p>$\therefore$ ${r_3} = {r_0} \times {{{3^2}} \over 1}$</p>
<p>$\Rightarrow {r_0} \times {{{r_3}} \over 9}$</p>
<p>and ${r_4} = {r_0} \times {{{4^2}} \over 1}$</p>
<p>$= {{{r_3}} \over 9} \times 16$</p>
<p>$= {{16} \over 9}{r_3}$</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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