The number of radial node/s for $3 p$ orbital is :
Solution
<p>The number of radial nodes in an orbital is given by the formula:</p>
<p>$\text{Number of radial nodes} = n - l - 1$</p>
<p>where
$n$ is the principal quantum number,
$l$ is the azimuthal quantum number also known as the angular momentum quantum number.</p>
<p>For a $3p$ orbital,
<br/><br/>$n = 3$ (since it is the 3rd energy level),
<br/><br/>$l = 1$ (since $p$ orbitals correspond to $l = 1$).</p>
<p>Let's use the formula to determine the number of radial nodes:</p>
<p>$\text{Number of radial nodes} = 3 - 1 - 1 = 1$</p>
<p>So, the correct answer is:
Option C : 1</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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