If the work function of a metal is 6.63 $\times$ 10$-$19J, the maximum wavelength of the photon required to remove a photoelectron from the metal is ____________ nm. (Nearest integer)
[Given : h = 6.63 $\times$ 10$-$34 J s, and c = 3 $\times$ 108 m s$-$1]
Answer (integer)
300
Solution
<p>Given,</p>
<p>Work function = 6.63 $\times$ 10<sup>$-$19</sup> J</p>
<p>$= {{6.63 \times {{10}^{ - 19}}} \over {1.6 \times {{10}^{ - 19}}}}$</p>
<p>= 4.14 eV</p>
<p>We know,</p>
<p>$E = {{1240} \over {\lambda \,(nm)}}$</p>
<p>$\Rightarrow 4.14 = {{1240} \over \lambda }$</p>
<p>$\lambda$ = 300 nm</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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