Consider the following pairs of electrons

(A) (a) n = 3, $l$ = 1, m₁ = 1, m_s = + ${1 \over 2}$

      (b) n = 3, 1 = 2, m₁ = 1, m_s = + ${1 \over 2}$

(B) (a) n = 3, $l$ = 2, m₁ = $-$2, m_s = $-$${1 \over 2}$

      (b) n = 3, $l$ = 2, m₁ = $-$1, m_s = $-$${1 \over 2}$

(C) (a) n = 4, $l$ = 2, m₁ = 2, m_s = + ${1 \over 2}$

      (b) n = 3, $l$ = 2, m₁ = 2, m_s = + ${1 \over 2}$

The pairs of electrons present in degenerate orbitals is/are :

1. A Only (A)
2. B Only (B) Correct answer
3. C Only (C)
4. D (B) and (C)