Consider the hypothetical situation where the azimuthal quantum number, $l$, takes values 0, 1, 2, ....., n + 1, where n is the principal quantum number. Then, the element with atomic number :
Solution
Under hypothetical situation, the value of l is
greater than n which varies from 0 to n + 1.
<br><br>For n = 1, l = 0, 1, 2
<br><br>n = 2, l = 0, 1, 2, 3
<br><br>Elements follow the following electronic
configuration
<br><br>1s 1p 1d 2s 2p 2d 2f
<br><br>Atomic number (Z) = 9
<br>1s<sup>2</sup> 1p<sup>6</sup> 1d<sup>1</sup>
<br><br>Atomic number = 6
<br>1s<sup>2</sup> 1p<sup>4</sup>
<br><br>Atomic number 8
<br>1s<sup>2</sup> 1p<sup>6</sup>
<br><br>Atomic number 13
<br>1s<sup>2</sup> 1p<sup>6</sup> 1d<sup>5</sup> (half filled)
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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