The maximum number of orbitals which can be identified with $\mathrm{n}=4$ and $m_l=0$ is _________.
Answer (integer)
4
Solution
<p>Possible combination of first three quantum numbers are</p>
<p>$$\begin{aligned}
& n=4, l=3, m=0 \\
& n=4, l=2, m=0 \\
& n=4, l=1, m=0 \\
& n=4, l=0, m=0
\end{aligned}$$</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
This question is part of PrepWiser's free JEE Main question bank. 122 more solved questions on Atomic Structure are available — start with the harder ones if your accuracy is >70%.