Easy
MCQ
+4 / -1
PYQ · JEE Mains 2025
In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields?
A. $\mathrm{n}=1, \mathrm{l}=0, \mathrm{~m}_1=0$
B. $\mathrm{n}=2, \mathrm{l}=0, \mathrm{~m}_1=0$
C. $\mathrm{n}=2, \mathrm{I}=1, \mathrm{~m}_1=1$
D. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=1$
E. $\mathrm{n}=3, \mathrm{l}=2, \mathrm{~m}_1=0$
Choose the correct answer from the options given below:
-
A
B and C Only
-
B
C and D Only
-
C
A and B Only
-
D
D and E Only
Correct answer
Solution
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<table class="tg" style="undefined;table-layout: fixed; width: 330px"><colgroup>
<col style="width: 225px">
<col style="width: 105px">
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<thead>
<tr>
<th class="tg-0lax"></th>
<th class="tg-baqh">orbital</th>
</tr></thead>
<tbody>
<tr>
<td class="tg-0lax">$\mathrm{A}: \mathrm{n}=1, \ell=0, \mathrm{~m}_{\ell}=0$</td>
<td class="tg-0lax">1s</td>
</tr>
<tr>
<td class="tg-0lax">$\mathrm{B}: \mathrm{n}=2, \ell=0, \mathrm{~m}_{\ell}=0$</td>
<td class="tg-0lax">2s</td>
</tr>
<tr>
<td class="tg-0lax">$\mathrm{C}: \mathrm{n}=3, \ell=1, \mathrm{~m}_{\ell}=1$</td>
<td class="tg-0lax">3p</td>
</tr>
<tr>
<td class="tg-0lax">$\mathrm{D}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=1$</td>
<td class="tg-0lax">3d</td>
</tr>
<tr>
<td class="tg-0lax">$\mathrm{E}: \mathrm{n}=3, \ell=2, \mathrm{~m}_{\ell}=0$</td>
<td class="tg-0lax">3d</td>
</tr>
</tbody>
</table></p>
<p>In absence of electric and magnetic fields, all orbitals of 3d are degenerate</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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