Consider an imaginary ion ${ }_{22}^{48} \mathrm{X}^{3-}$. The nucleus contains '$a$'% more neutrons than the number of electrons in the ion. The value of 'a' is _______________. [nearest integer]
Answer (integer)
4
Solution
Number of electrons in ${ }_{22}^{48} X^{3-}$ is 25 .
<br/><br/>
Number of neutrons $=48-22=26$.
<br/><br/>
$\%$ increase in the number of neutrons over electrons
<br/><br/>
$=\left(\frac{26-25}{25}\right) 100=4 \%$
<br/><br/>
$\therefore a=4$
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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