The minimum energy that must be possessed by photons in order to produce the photoelectric effect with platinum metal is :
[Given : The threshold frequency of platinum is 1.3 $\times$ 1015 s$-$1 and h = 6.6 $\times$ 10$-$34 J s.]
Solution
<p>The minimum energy possessed by photons will be
equal to the work function of the metal.</p>
<p>$\therefore$ E<sub>min</sub> = h$\nu$<sub>0</sub> J</p>
<p>= 6.6 $\times$ 10<sup>$-$34</sup> $\times$ 1.3 $\times$ 10<sup>15</sup></p>
<p>= 8.58 $\times$ 10<sup>$-$19</sup> J</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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