The number of orbitals with n = 5, m1 = +2 is ___________. (Round off to the Nearest Integer).
Answer (integer)
3
Solution
<p>Given, n = 5, m<sub>l</sub> = + 2</p>
<p>For n = 5, possible value of l = 0, 1, 2, 3, 4</p>
<p>For l = 0, m<sub>l</sub> = 0</p>
<p>l = 1, m<sub>l</sub> = $-$1, 0, 1</p>
<p>l = 2, m<sub>l</sub> = $-$2, $-$1, 0, 1, 2</p>
<p>l = 3, m<sub>l</sub> = $-$3, $-$2, $-$1, 0, 1, 2, 3</p>
<p>l = 4, m<sub>l</sub> = $-$4, $-$3, $-$2, $-$1, 0, 1, 2, 3, 4</p>
<p>Possible value of m<sub>l</sub> for a given value of l</p>
<p>= 0, $\pm$ 1, $\pm$ 2, $\pm$ 3 ..... $\pm$ l</p>
<p>So, number of orbitals having n = 5 and m<sub>l</sub> = $\pm$ 2 are 3.</p>
About this question
Subject: Chemistry · Chapter: Atomic Structure · Topic: Bohr's Model
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