Easy MCQ +4 / -1

Benzenediazonium chloride is prepared by:

  1. A Reducing nitrobenzene
  2. B Treating aniline with NaNO₂ + HCl at 0-5°C Correct answer
  3. C Oxidising aniline
  4. D Reacting phenol with ammonia

Solution

Aniline + NaNO₂ + HCl at 0-5°C → benzenediazonium chloride (C₆H₅N₂⁺Cl⁻). Low temperature is essential to prevent decomposition.

About this question

Subject: Chemistry · Chapter: Amines · Topic: Diazonium Salts

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