Vanillin compound obtained from vanilla beans, has total sum of oxygen atoms and $\pi$ electrons is __________.
Answer (integer)
11
Solution
<p>To determine the total sum of oxygen atoms and $\pi$ electrons in vanillin, let's first consider the structure of vanillin. Vanillin is an organic compound with the chemical formula $C_8H_8O_3$. It consists of a benzene ring attached to a methoxy group (-OCH<sub>3</sub>), a hydroxyl group (-OH), and an aldehyde group (-CHO).</p>
<p>Firstly, let's count the oxygen atoms:</p>
<ul>
<li>One from the methoxy group (-OCH<sub>3</sub>)</li>
<li>One from the hydroxyl group (-OH)</li>
<li>One from the aldehyde group (-CHO)</li>
</ul>
<p>Thus, there are a total of 3 oxygen atoms in vanillin.</p>
<p>Next, let's calculate the total number of $\pi$ electrons:</p>
<ul>
<li>The benzene ring has 3 double bonds, contributing 6 $\pi$ electrons.</li>
<li>The aldehyde group has 1 double bond (C=O), contributing 2 $\pi$ electrons.</li>
<li>The methoxy group and the hydroxyl group do not contribute any $\pi$ electrons since they do not have $\pi$ bonds in their structures.</li>
</ul>
<p>Therefore, vanillin has a total of 8 $\pi$ electrons from the benzene ring and the aldehyde group.</p>
<p>Adding the number of oxygen atoms (3) and the $\pi$ electrons (8) gives us a total sum of 11.</p>
<p>Thus, the total sum of oxygen atoms and $\pi$ electrons in vanillin is <strong>11</strong>.</p>
About this question
Subject: Chemistry · Chapter: Aldehydes, Ketones and Carboxylic Acids · Topic: Nucleophilic Addition Reactions
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